Probability Concepts
Independent vs Mutually Exclusive Events: What Is the Difference?
Independent events do not affect each other's probability, so P(A and B) = P(A) × P(B). Mutually exclusive events cannot happen together, so P(A and B) = 0. They are different ideas, and they rule each other out: apart from events that never happen, two mutually exclusive events are always dependent. A six on each of two rolls of a die is independent, with P(both) = 1/36. A six and a five on one roll are mutually exclusive, with P(both) = 0.
The two definitions side by side
Two events A and B can be related in two different ways. They can affect each other's probability (independence), or they can rule each other out (mutual exclusivity). The first is about how likely one event is once the other is known; the second is about whether both can happen at all.
| Independent events | Mutually exclusive events | |
|---|---|---|
| In words | Knowing that one happened does not change the probability of the other | They cannot both happen in the same trial |
| Test | P(A and B) = P(A) × P(B) | P(A and B) = 0 |
| P(A and B) | P(A) × P(B) | 0 |
| P(A or B) | P(A) + P(B) − P(A) × P(B) | P(A) + P(B) |
| P(A given B) | P(A) | 0 |
| Venn diagram | The circles overlap by exactly P(A) × P(B) | The circles do not overlap |
| Example | A six on the first roll and a six on the second roll | A six and a five on the same roll |
The same probabilities in both situations
Take two events that each have probability 1/6. In the first situation they are a six on the first roll of a die and a six on the second roll, which are independent. In the second they are a six and a five on one roll, which are mutually exclusive. The probabilities of the single events are the same; everything else differs.
| Two rolls (independent) | One roll (mutually exclusive) | |
|---|---|---|
| P(A) and P(B) | 1/6 each | 1/6 each |
| P(A and B) | 1/36 ≈ 0.027778 | 0 |
| P(A or B) | 11/36 ≈ 0.305556 | 1/3 ≈ 0.333333 |
| P(neither) | 0.694444 | 0.666667 |
| P(A given B) | 1/6 ≈ 0.166667 | 0 |
With independent events P(A or B) = 1/6 + 1/6 − 1/36 = 11/36, because both can happen and the overlap is counted once. With mutually exclusive events there is no overlap to subtract, so P(A or B) = 1/6 + 1/6 = 1/3. Enter 1/6 and 1/6 in the probability of multiple events calculator and switch between "Independent" and "Mutually exclusive" to see both columns.
Why mutually exclusive events are not independent
It is tempting to think that events which do not affect each other must be mutually exclusive, or the other way round. In fact the two properties pull in opposite directions.
- Mutually exclusive events with positive probabilities are dependent. If a die shows a five, it cannot show a six. So P(six given five) = 0, while P(six) = 1/6. Learning that B happened changed the probability of A, which is exactly what dependence means.
- Independent events with positive probabilities can happen together. If P(A) > 0 and P(B) > 0, independence gives P(A and B) = P(A) × P(B) > 0, so the two events overlap and are not mutually exclusive.
The two properties can only meet when a probability is 0. Mutually exclusive means P(A and B) = 0 and independent means P(A and B) = P(A) × P(B), so both hold only if P(A) × P(B) = 0. An event that never happens, such as rolling a 7 on a standard die, is independent of every event and mutually exclusive with every event. That is a technical exception and not a useful case.
How to tell which one you have
- Can both events happen in the same trial? If not, they are mutually exclusive, and therefore dependent whenever both have a chance of happening.
- If they can overlap, find P(A and B). Count the outcomes in both events, or use the probability you are given.
- Compare it with P(A) × P(B). Equal means independent; different means dependent. A larger P(A and B) means the events tend to happen together, a smaller one that they tend to avoid each other.
The table applies the steps to four situations.
| Situation | P(A) | P(B) | P(A and B) | P(A) × P(B) | Verdict |
|---|---|---|---|---|---|
| A king and a heart from one card | 1/13 | 1/4 | 1/52 | 1/52 | Independent, they overlap on the king of hearts |
| A king and a queen from one card | 1/13 | 1/13 | 0 | 1/169 | Mutually exclusive, and so dependent |
| P(A) and P(B) given, with P(A and B) = 0.3 | 0.4 | 0.5 | 0.3 | 0.2 | Neither: they overlap, but not by the independent amount |
| P(A) and P(B) given, with P(A and B) = 0.2 | 0.4 | 0.5 | 0.2 | 0.2 | Independent |
For a king and a heart, P(A or B) = 1/13 + 1/4 − 1/52 = 4/13 ≈ 0.307692. For a king or a queen there is nothing to subtract: 1/13 + 1/13 = 2/13 ≈ 0.153846. For the third row P(A or B) = 0.4 + 0.5 − 0.3 = 0.6, and P(A given B) = 0.3 / 0.5 = 0.6, which differs from P(A) = 0.4, so knowing B raises the probability of A.
Formulas for both cases
General: P(A or B) = P(A) + P(B) − P(A and B)
General: P(A and B) = P(A) × P(B given A)
Independent: P(A and B) = P(A) × P(B), and P(A given B) = P(A)
Independent: P(A or B) = P(A) + P(B) − P(A) × P(B) = 1 − (1 − P(A)) × (1 − P(B))
Mutually exclusive: P(A and B) = 0, and P(A or B) = P(A) + P(B)
The general rules always hold; the shortcuts apply only when you know the relationship. When you know P(A), P(B) and P(A and B), the general formulas need no assumption at all. For the probability of A when B is known, see the conditional probability calculator, and for how a probability is updated by evidence, Bayes' theorem explained.
Dependent events that are not exclusive
Most real events are neither independent nor mutually exclusive: they can happen together, but one changes the chance of the other. Drawing cards without replacement is the standard case. The chance of an ace is 4/52 = 1/13 for the first card, but 3/51 for the second card if the first was an ace. Two aces in a row therefore have probability 4/52 × 3/51 = 1/221 ≈ 0.004525, while two aces with the first card put back have probability 1/13 × 1/13 = 1/169 ≈ 0.005917. Use the "Dependent events, one after another" mode of the multiple events calculator for such chains. The difference between sampling with and without replacement also separates the binomial and hypergeometric distributions; see binomial vs Poisson vs hypergeometric.
Common mistakes
- Calling events independent because they do not influence each other physically. Independence is a statement about probabilities: check that P(A and B) = P(A) × P(B), or that P(A given B) = P(A).
- Adding the probabilities of events that can happen together. P(A) + P(B) counts the overlap twice unless the events are mutually exclusive; subtract P(A and B). For a king or a heart, 1/13 + 1/4 = 17/52 is too large by 1/52.
- Multiplying the probabilities of mutually exclusive events. P(A) × P(B) is not P(A and B) here: for a king and a queen it would give 1/169 when the true value is 0.
- Treating draws without replacement as independent. The second draw depends on the first, as the two aces show.
- Believing that mutually exclusive events are independent because they are unrelated. They are the most strongly related pair possible: one happening rules the other out.
Try the Probability of Multiple Events Calculator
P(A and B), P(A or B), P(A only), P(neither) and P(A given B) for independent, mutually exclusive or overlapping events.
Try the Conditional Probability Calculator
P(A given B) from counts or from P(A and B), the quantity that defines independence.
Frequently Asked Questions
What is the difference between independent and mutually exclusive events?
Independent events do not change each other's probability, so P(A and B) = P(A) × P(B). Mutually exclusive events cannot happen in the same trial, so P(A and B) = 0. A six on each of two dice rolls is independent (both happen with probability 1/36); a six and a five on one roll are mutually exclusive (both never happen).
Are mutually exclusive events independent?
No, unless one of them has probability 0. If A and B are mutually exclusive and both can happen, then once B has happened A is impossible: P(A given B) = 0, which is different from P(A). Rolling a six has probability 1/6, but given that the roll was a five it has probability 0, so the two events are dependent.
Can two events be both independent and mutually exclusive?
Only when at least one of them has probability 0. Mutually exclusive requires P(A and B) = 0 and independent requires P(A and B) = P(A) × P(B), so P(A) × P(B) must be 0. An event that never happens, such as rolling a 7 on a standard die, is independent of every event and mutually exclusive with every event.
How do you know if two events are independent?
Compare P(A and B) with P(A) × P(B). If they are equal the events are independent; if not, they are dependent. Equivalently, P(A given B) equals P(A). For P(A) = 0.4, P(B) = 0.5 and P(A and B) = 0.3 the product is 0.2, which differs from 0.3, so the events are dependent.
What is the formula for P(A or B) for each kind of event?
In general P(A or B) = P(A) + P(B) − P(A and B). For mutually exclusive events P(A and B) = 0, so P(A or B) = P(A) + P(B). For independent events P(A and B) = P(A) × P(B), so P(A or B) = P(A) + P(B) − P(A) × P(B). With P(A) = P(B) = 1/6 these give 1/3 and 11/36.
Are two draws from a deck without replacement independent?
No. The first card changes what is left in the deck. The probability of a second ace is 4/52 = 1/13 before any card is drawn, but 3/51 after an ace has been drawn, so two aces in a row have probability 4/52 × 3/51 = 1/221 ≈ 0.004525. With replacement the draws are independent and the probability is 1/13 × 1/13 = 1/169 ≈ 0.005917.
Are complementary events mutually exclusive?
Yes: A and not A can never happen together, and together they cover every outcome, so P(A) + P(not A) = 1. They are also dependent, because knowing that A happened tells you that not A did not, unless P(A) is 0 or 1.
Are disjoint events the same as mutually exclusive events?
Yes. Disjoint events and mutually exclusive events are two names for events with no outcome in common, so P(A and B) = 0. In a Venn diagram their circles do not overlap.